The height (in meters) of a projectile shot vertically upward from a point 2 meters above ground level with an initial velocity of 24.5 meters per second is given by the equation:
\[ h = 2 + 24.5t - 4.9t^2 \]
where \( h \) is the height after \( t \) seconds.
1. When does the projectile hit the ground?
2. With what velocity does it hit the ground?
Answer (2)
For the moment one hits the ground, you set h=0 and solve for t. To find out the speed, you must find out v = 24.5 − 9.8 t
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