25 ;
f(x)=|(x^2-50)|\\\\f(-5)=|(-5)^2-50|=|25-50|=|-25|=25\\\\\\|a|= \left\{\begin{array}{ccc}a&for&a\geq0\\-a&for&a < 0\end{array}\right\\\\|-3|=3;\ |5|=5;\ |0|=0;\ |-12|=12
The value of the function f ( x ) = ∣ x 2 − 50∣ at x = − 5 is 25 . This is calculated by substituting − 5 into the function, simplifying, and applying absolute value. The final result is 25 .
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