What is the missing dimension of a parallelogram if \( h = 5 \frac{1}{4} \) feet and \( A = 12 \) feet\(^2\)?
Answer (2)
The missing is the base A=bh 12= 5.25b Divide both sides by 5.25 b=2.29 ft
The missing dimension of the parallelogram, which is the base, is approximately 2.29 feet when the height is 5.25 feet and the area is 12 square feet. This is calculated using the area formula A = b × h .
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