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In Mathematics / High School | 2014-03-20

One gallon of fuel mixture contains antifreeze in the ratio of 5 parts fuel to one part antifreeze. To this is added half a gallon of mixture which is one third antifreeze and two thirds fuel. What is the ratio of fuel to antifreeze in the final mixture?

Asked by Klasinski746

Answer (2)

1 gal (initial) = (5/6) parts fuel & (1/6) parts antifreeze= total of 6 parts 0.5 gal (add'l) = (2/3) parts fuel & (1/3) parts antifreeze = total of 3 parts
adding the two Fuel: 1gal*(5/6 parts) + 0.5gal*(2/3 parts) = 7/6 parts in 1.5 total gallons Antifreeze: 1gal*(1/6 parts) + 0.5gal*(1/3 parts) = 2/6 parts in 1.5 total gallons
thus with a common denominator provides a ratio of 7:2 (fuel:antifreeze)

Answered by Anonymous | 2024-06-10

After combining the two fuel mixtures, the final ratio of fuel to antifreeze in the mixture is 7:2. This ratio was achieved by calculating the amounts of fuel and antifreeze in both mixtures and summing them. The detailed steps show how to arrive at this conclusion clearly.
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Answered by Anonymous | 2024-09-26