It takes 56.5 kilojoules of energy to raise the temperature of 150 milliliters of water from 5°C to 95°C. If you use an electric water heater that is 60% efficient, how many kilojoules of electrical energy will the heater actually use by the time the water reaches its final temperature?

You'd get an extra 40/60 of the energy, or 2/3. Multiply 5/3 by the required energy to get the actual consumption.

Answered by Anonymous | 2024-06-10

The electric water heater will use approximately 94.17 kilojoules of electrical energy to heat the water due to its 60% efficiency. This is calculated by dividing the needed energy of 56.5 kJ by the efficiency. Thus, the total energy input required is higher than the useful energy output because of the efficiency loss.
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Answered by Anonymous | 2024-10-14