V = pi() * R^2 * (h/3)
pi() = 3.14159 approx R = 5 inches max (since max diameter = 10 in) h max = 10 inches
plug and chug
V = 261.8 in^3 = 1.82 ft^3
The volume of the largest cone that can fit into a cube with edges of 10 inches is approximately 261.8 cubic inches. This is calculated using the formula for the volume of a cone, substituting the radius and height accordingly. The radius is 5 inches, and the height is 10 inches.
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