Factor completely:

\[ 4x^3 - 36x \]

You would take out a 4x out of both terms because this is a common factor 4x^3-36x 4x(x^2-9) and then you would notice that (x^2-9) is a difference of squares, so that factors out too 4x(x-3)(x+3) that is all you can factor! hope this helps

Answered by HannahN | 2024-06-10

the factor of this is 4x(x^2-9) then x^2-9 can be factored using sum and difference. 4x(x+3)(x-3)

Answered by deathstrike001 | 2024-06-10

To completely factor the expression 4 x 3 − 36 x , first factor out the common factor 4 x , resulting in 4 x ( x 2 − 9 ) . Then, recognize that x 2 − 9 is a difference of squares, which can be factored as ( x − 3 ) ( x + 3 ) . Therefore, the complete factorization is 4 x ( x − 3 ) ( x + 3 ) .
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Answered by HannahN | 2024-12-23