Y=x^3+125
Needs to be factored

a 3 + b 3 = ( a + b ) ( a 2 − ab + b 2 ) y = x 3 + 125 = x 3 + 5 3 = ( x + 5 ) ( x 2 − 5 x + 5 2 ) = ( x + 5 ) ( x 2 − 5 x + 25 )

Answered by Anonymous | 2024-06-10

The expression y = x 3 + 125 can be factored using the sum of cubes formula. The factored form is ( x + 5 ) ( x 2 − 5 x + 25 ) . This provides an easier way to work with the polynomial in various mathematical contexts.
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Answered by Anonymous | 2024-10-01