Solve the given polynomial equation. Use the Rational Zero Theorem and Descartes' Rule of Signs as an aid in obtaining the first root.
\[ 6x^3 - 7x^2 - 6x - 1 = 0 \]
What is the solution set?
Answer (2)
Decartes rule! Haha if I get this right it should be 0 positives because the signs never change and 2 negative zeros I believe if you replace the x with -x
If you need the p+q's just ask here and I'll help more :D
To find the roots for 6 x 3 − 7 x 2 − 6 x − 1 = 0 , we used the Rational Root Theorem and Descartes' Rule of Signs. We found a rational root of − 2 1 and then factored the polynomial, leading to two additional roots from the quadratic factor. The final roots are − 2 1 , 12 10 + 2 37 , 12 10 − 2 37 .
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