Determine the equation in the form \( y = mx + b \) for the line passing through each pair of points: (0, 8) and (4, 3).

y=mx+b\\\\A(0;\ 8);\ B(4;\ 3)\\\\substitution\\\\ \left\{\begin{array}{ccc}0m+b=8\\4m+b=3\end{array}\right\\\\\left\{\begin{array}{ccc}b=8\\4m+b=3\end{array}\right\\\left\{\begin{array}{ccc}b=8\\4m+8=3\end{array}\right\\\left\{\begin{array}{ccc}b=8\\4m=3-8\end{array}\right\\\left\{\begin{array}{ccc}b=8\\4m=-5&/:4\end{array}\right\left\{\begin{array}{ccc}b=8\\m=-\frac{5}{4}\end{array}\right
A n s w er : y = − 4 5 ​ x + 8

Answered by Anonymous | 2024-06-10

This requires y2 - y1/ x2 - x1 as the slope. I got y=-5/4x+8 as my answer

Answered by MathG33k | 2024-06-10

The equation of the line passing through the points (0, 8) and (4, 3) is given by y = − 4 5 ​ x + 8 . The slope of the line is − 4 5 ​ and the y-intercept is 8.
;

Answered by Anonymous | 2024-12-23