Write an equation in slope-intercept form of a line that passes through the point (2, 4) and is perpendicular to the graph of \( x - 6y = 2 \).

-6y=2-x y=x/6-1/3 so the slope for this line is 1/6, therefore the slope for line perpendicular to this line is -6 y=mx+b subsitute (2,4)in 4=-6*2+b you get b=16 so the equation is y=-6x+16

Answered by a630061087 | 2024-06-10

The equation of the line that is perpendicular to x − 6 y = 2 and passes through the point ( 2 , 4 ) is y = − 6 x + 16 . This was found by first determining the slope of the original line, finding its negative reciprocal for the perpendicular slope, and then using the point-slope form to find the equation. Finally, we simplified the result to slope-intercept form.
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Answered by a630061087 | 2024-12-20