Solve the system of equations using substitution.

\[ y = \frac{3}{4}x - 7 \]

\[ 4x - 6y = 50 \]

{ y = 4 3 ​ x − 7 4 x − 6 y = 50 ​ { y = 4 3 ​ x − 7 4 x − 6 ( 4 3 ​ x − 7 ) = 50 ​ { y = 4 3 ​ x − 7 4 x − 2 9 ​ x + 42 = 50 ​ { y = 4 3 ​ x − 7 4 x − 4 2 1 ​ x = 50 − 42 ​
{ y = 4 3 ​ x − 7 − 2 1 ​ x = 8 / ∗ ( − 2 ) ​ { y = 4 3 ​ ∗ ( − 16 ) − 7 x = − 16 ​ { y = − 12 − 7 x = − 16 ​ { y = − 19 x = − 16 ​

Answered by Lilith | 2024-06-10

Y=3/4x-7 4x-6y=50
4x-6y=50 4x-6(3/4x-7)=50 4x-18/4x+42=50 -1/2x=8 x=-16
y=3/4(-16)-7 y=-12-7 y=-19

Answered by deathstrike001 | 2024-06-10

By substituting the expression for y into the second equation, we solve for x and find that x = -16. We then substitute x back to find y = -19. Thus, the solution to the system of equations is (x, y) = (-16, -19).
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Answered by Lilith | 2024-12-23