Solve by elimination:
\[ x + 2y = 7 \]
\[ 3x - 2y = -3 \]
Answer (2)
+\left\{\begin{array}{ccc}x+2y=7\\3x-2y=-3\end{array}\right\\---------\\x+3x=7+(-3)\\4x=4\ \ \ \ /:4\\x=1\\\\\left\{\begin{array}{ccc}x=1\\x+2y=7\end{array}\right\\\left\{\begin{array}{ccc}x=1\\1+2y=7&/-1\end{array}\right\\\left\{\begin{array}{ccc}x=1\\2y=6&/:2\end{array}\right\\\left\{\begin{array}{ccc}x=1\\y=3\end{array}\right\\
By using the elimination method, we found that x = 1 and y = 3 are the solutions to the system of equations. The solution can be verified by substituting the values back into the original equations. Therefore, the solution is ( x , y ) = ( 1 , 3 ) .
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