Solve the following quadratic equation:

\[ 16x^2 - 81 = 0 \]

16 x 2 − 81 = 0 ( 4 x ) 2 − 9 2 = 0 ( 4 x − 9 ) ( 4 x + 9 ) = 0 ⟺ 4 x − 9 = 0 ∨ 4 x + 9 = 0 4 x = 9 ∨ 4 x = − 9 x = 4 9 ​ ∨ x = − 4 9 ​
or 16 x 2 − 81 = 0 16 x 2 = 81 / : 16 x 2 = 16 81 ​ x = ± 16 81 ​ ​ x = − 16 ​ 81 ​ ​ ∨ x = 16 ​ 81 ​ ​ x = − 4 9 ​ ∨ x = 4 9 ​

Answered by Anonymous | 2024-06-10

16x^2-81=0 (4x-9)(4x+9) x=9/4 or x=-9/4

Answered by deathstrike001 | 2024-06-10

The solutions to the quadratic equation 16 x 2 − 81 = 0 are x = 4 9 ​ and x = − 4 9 ​ . This is obtained by isolating x 2 and taking the square root of both sides. Hence, we have two possible values for x.
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Answered by Anonymous | 2024-12-23