2 v 2 − 5 v + 3 = 0 Δ = b 2 − 4 a c = ( − 5 ) 2 − 4 ∗ 2 ∗ 3 = 25 − 24 = 1 v 1 = 2 a − b − Δ = 2 ∗ 2 5 − 1 = 4 5 − 1 = 4 4 = 1 v 2 = 2 a − b + Δ = 2 ∗ 2 5 + 1 = 4 5 + 1 = 4 6 = 2 3 = 1 2 1
The quadratic equation 2 v 2 − 5 v + 3 = 0 can be solved using the quadratic formula. The solutions are v = 1 and v = 1.5 .
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