area of field=xy=5000 perimeter of field=2(x+y)300 x+y=150 x=150-y y(150-y)=5000 y 2 − 150 y + 5000 = 0 solve it u get y= 50 or 100 then x=100 or 50 therefore the dimensions are 100m and 50m
To determine the dimensions of the rectangular field, we set up equations for the area and perimeter. By solving the quadratic equation obtained from these formulas, we find that the dimensions are 100 m and 50 m. Thus, the field can either be 100 m long and 50 m wide or vice versa.
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