Can somebody help and explain the equation [tex]\log_b 121 = 2[/tex]?
Answer (3)
0\ \wedge\ b\neq1\\\\\\\log_ab=c\iff a^c=b"> l o g b 121 = 2 ⟺ b 2 = 121 → b = 121 → b = 11 b > 0 ∧ b = 1 lo g a b = c ⟺ a c = b
l o g b 121 = 2 l o g b 1 1 2 = 2 2 l o g b 11 = 2 l o g b 11 = 1 therefore b=11
The equation lo g b 121 = 2 means that the base b raised to the power of 2 equals 121. Therefore, we find that b is 11, as 1 1 2 = 121 . This demonstrates an important property of logarithms, where base conditions must be met as well.
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