A
telephone pole breaks and falls as shown. To the nearest foot, what was the
original height of the pole?

the original height of the pole is 18 feet

Answered by adeaton | 2024-06-10

The original height of the telephone pole is approximately 19 feet, obtained by adding the hypotenuse (calculated using the Pythagorean Theorem) to the height of the triangle formed (7 feet). The nearest provided option is a. 19 ft.
To find the original height of the telephone pole, you can use the Pythagorean Theorem:
In this case, the right-angled triangle is formed by the telephone pole. The given sides are the base (b = 10 ft) and the height (a = 7 ft).
c 2 = a 2 + b 2
Substitute the given values:
c 2 = 7 2 + 1 0 2 c 2 = 49 + 100 c 2 = 149 \[ c = 149 ​ \ c ≈ 12.2 ]
The final height of the telephone pole is the sum of the hypotenuse and the height of the triangle formed:
Final height = Hypotenuse + Height of triangle Final height = 149 + 7 ​
Now, calculate this value:
Final height ≈ 12.2 + 7 ≈ 19.2
Rounding to the nearest foot, the final height is approximately 19 feet.
So, the closest option among the provided choices is:
a. 19 ft.

Answered by sameer362097 | 2024-06-24

Using the Pythagorean Theorem, the original height of the telephone pole is determined to be approximately 78 feet. This calculation is based on the height of the break and the horizontal distance from the base to the fall line. The theorem provides a way to find the length (height) of the pole from the known measurements.
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Answered by sameer362097 | 2024-10-13