{ y = 6 x − 3 y = − x + 4 { y = 6 x − 3 6 x − 3 = − x + 4 { y = 6 x − 3 6 x + x = 4 + 3 { y = 6 x − 3 7 x = 7 / : 7 { y = 6 ∗ 1 − 3 x = 1 { y = 3 x = 1
To solve the system of equations y = 6 x − 3 and y = − x + 4 , set the equations equal to each other, solve for x , and then substitute back to find y . The solution is ( x , y ) = ( 1 , 3 ) . This method shows the relationship between the equations using substitution.
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