Solve the system of linear inequalities:

1. \(-2 \leq y \leq 6\)

2. \(3y \leq 4x + 26\)

3. \(y \leq -2x + 2\)

Objective function: \(f(x, y) = -3x - 6y\)

3y<=4x+26 y<-2x+2
Multiply the second equation by 2 to eliminate y 3y<=4x+26 2y<=-4x+4
5y<=30 Divide both sides by 5 y<=6
Substitute the value lets say y=6 6<=-2x+2 4<=-2x -2>=x

Answered by deathstrike001 | 2024-06-10

To solve the given inequalities, we analyze each inequality to find the restricted values of x and y. The intersection points define a feasible region, where we can evaluate the objective function f ( x , y ) = − 3 x − 6 y at those points to find the optimal solution. Graphing these inequalities can further aid in understanding the solution set visually.
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Answered by deathstrike001 | 2024-12-23