Solve the following system of linear equations:
\[
3x + 2y = 11
\]
\[
7x - y = 3
\]
Answer (2)
{ 3 x + 2 y = 11 7 x − y = 3 { 3 x + 2 ∗ ( 7 x − 3 ) = 11 y = 7 x − 3 { 3 x + 14 x − 6 = 11 y = 7 x − 3 { 17 x = 11 + 6 y = 7 x − 3
{ 17 x = 17 / : 17 y = 7 x − 3 { x = 1 y = 7 ∗ 1 − 3 { x = 1 y = 4
The solution to the system of equations is (x, y) = (1, 4). This was found using substitution, isolating y in one equation and substituting into the other. Both original equations were satisfied with the values found.
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