Solve by completing the square:
\[ x^2 + 14x - 51 = 0 \]
Answer (2)
x 2 + 14 x − 51 = 0 Δ = b 2 − 4 a c = 1 4 2 − 4 ∗ 1 ∗ ( − 51 ) = 196 + 204 = 400 x 1 = 2 a − b − Δ = 2 − 14 − 400 = 2 − 14 − 20 = 2 − 34 = − 17 x 2 = 2 a − b + Δ = 2 − 14 + 400 = 2 − 14 + 20 = 2 6 = 3
By completing the square for the equation x 2 + 14 x − 51 = 0 , we moved the constant to the right, completed the square on the left side, and found the solutions x = 3 and x = − 17 .
;
