A + B = 76 → A = 76 − B A − B = 38 → A = 38 + B ⇓ 38 + B = 76 − B B + B = 76 − 38 2 B = 38 / : 2 B = 19 ⇓ A = 76 − 19 = 57
⇓ A : B = 57 : 19 = 3
B A = 3 ; For this case we have the following system of equations:
[ A + B = 76
A-B = 38 ]
Solving the system of equations we have:
**1) **We subtract equation 1 with equation 2:
[ 2B = 76 - 38
2B = 38 ]
2) We clear the value of B:
[ B = \frac{38}{2}
B = 19 ]
3) We substitute The value of B in equation 2 and obtain the value of A:
[ A-B = 38
A-19 = 38
A = 38 + 19
A = 57 ]
Then, the value of the division of both numbers is:
B A = 19 57 = 3
By solving the equations A + B = 76 and A − B = 38 , we find that A = 57 and B = 19 . Therefore, A ÷ B = 19 57 ≈ 3 .
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