Tanx = 3/4 = Y/X = opps/adj
sqrt(3^2+4^2) = 5 = hypotenuse
Cos is adj/hyp
Cosx = 4/5
t an x = 4 3 t an x = cos x s in x cos x s in x = 4 3 → s in x = 4 3 cos x ( ∗ ) s i n 2 x + co s 2 x = 1 s u b s t i t u t e ( ∗ ) ( 4 3 cos x ) 2 + co s 2 x = 1 16 9 co s 2 x + co s 2 x = 1
16 15 co s 2 x = 1 / ⋅ 25 16 co s 2 x = 25 16 cos x = 25 16 cos x = 5 4
Given tan x = 4 3 , we determined cos x = 5 4 using the relationship between tangent, sine, and cosine alongside the Pythagorean identity. This solution is valid within the range specified for x .
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