If [tex]\log 2^8 = \log 4 + \log x[/tex], what is the value of [tex]x[/tex]?

Question

amerikello · Answer

log4 + logx = log4x 4x = 28 x = 7 Easy cheesy! :) hope I helped. all you had to do is to divide 28/4 which is 7x

Anonymous · Answer

To solve lo g 2 8 = lo g 4 + lo g x , we simplified both sides using properties of logarithms. This gave us the equation 256 = 4 x , leading to x = 64 . Thus, the solution for x is 64. 
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If [tex]\log 2^8 = \log 4 + \log x[/tex], what is the value of [tex]x[/tex]?

Answer (2)

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