Please help me solve the system of equations:

1. \(3x + 10y = 48\)
2. \(7x + 4y = 54\)

3x+10y=48 7x+4y=54
multiply the first equation by 2 and the 2nd equation by 5 to remove y 6x+20y=96 35x+20y=270 29x=174 x=6
substitute to any equation 7x+4y=54 42+4y=54 4y=12 y=3
the value of x is 6 and the value of y is 3

Answered by deathstrike001 | 2024-06-10

**Answer: x=36/7 **
** y=9/2** ;

Answered by zidanethernandez8 | 2024-06-12

The solution to the system of equations is x = 6 and y = 3 . This can be found by eliminating one variable and then solving the resulting equations. The method used involved multiplying both equations to align coefficients and then subtracting them to isolate a variable.
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Answered by deathstrike001 | 2024-12-23