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In Mathematics / High School | 2014-04-01

Tickets to a play cost $5 for adults and $2 for children. If 1,750 tickets were sold for a total of $7,100, how many children’s tickets were sold?

Can someone explain how to solve this step by step?

Asked by JordonGarroutte807

Answer (3)

A total of 550 children's tickets were sold. This was determined by setting up a system of equations based on the total tickets sold and the total revenue, solving for the number of adult tickets, and then using that information to find the number of children's tickets sold. ;

Answered by sakshiprajapati688 | 2024-06-18

To solve this problem, we can set up a system of equations. Let x represent the number of adult tickets sold and y represent the number of children's tickets sold. We know that the cost of adult tickets is $5 and the cost of children's tickets is $2.
We can set up two equations to represent the total number of tickets sold as well as the total revenue earned. The first equation is x + y = 1750, since the total number of tickets sold is 1750. The second equation is 5x + 2y = 7100, since the total revenue earned is $7100.
We can now solve this system of equations. By multiplying the first equation by 2, we can eliminate y and find the value of x: 2x + 2y = 3500. Subtracting this equation from the second equation, we get 3x = 3600. Dividing by 3, we find x = 1200. Substituting this value back into the first equation, we can solve for y: 1200 + y = 1750. Solving for y, we find y = 550.
Therefore, 550 children's tickets were sold.

Answered by Darla1012 | 2024-06-24

In total, 550 children's tickets were sold. This was determined by setting up equations based on the total tickets sold and the total revenue, solving for the number of adult tickets, and then finding the number of children's tickets sold. The problem is solved using a systematic approach of substitution and simplification.
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Answered by sakshiprajapati688 | 2024-12-20

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