What is the 50th term of the arithmetic sequence 4, 10, 16, 22, … ?

298, also 4 is first term. 49 terms left. 49*6=294 294+4=298

Answered by runescapememo8 | 2024-06-10

The equation appropriate for this is a n ​ = a 1 ​ + ( n − 1 ) d Wherein n ​ is the missing term, a 1 ​ is the first number in the sequence, and d is the difference between the numbers. So a 50 ​ = 4 + ( 50 − 1 ) 6 a 50 ​ = 4 + ( 49 ∗ 6 ) a 50 ​ = 4 + ( 294 ) a 50 ​ = 298 *Sorry for the error.

Answered by Edmund | 2024-06-24

The 50th term of the arithmetic sequence 4, 10, 16, 22, ... is calculated to be 298. This is done using the formula for the n-th term of an arithmetic sequence by identifying the first term and the common difference. The calculations show that the 50th term results from adding 294 to the first term of 4.
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Answered by Edmund | 2024-09-05