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In Mathematics / High School | 2014-04-04

Video Club A charges $10 for membership and $3 per movie rental. Video Club B charges $15 for membership and $2 per movie rental.

For how many movie rentals will the cost be the same at both video clubs? What is that cost?

Asked by michelle101

Answer (3)

write an equation
10 + 3x = 15 +2x -2x -2x
10 + x (1x) = 15 -10 -10
x = 5
cost= 25 (10 + 15)

Answered by Anonymous | 2024-06-10

After 5 rentals, the cost of renting movies will be the same at both Video Club A and Video Club B, which is $25.

The question pertains to finding the point where the cost of renting movies from Video Club A equals the cost of renting movies from Video Club B, given their respective membership and rental charges. We let x represent the number of movie rentals.
For Video Club A: Total Cost = Membership + (Rental per movie times Number of rentals) = $10 + ($3 times x)
For Video Club B: Total Cost = Membership + (Rental per movie times Number of rentals) = $15 + ($2 times x)
To find the number of rentals for which costs are the same, we set the total costs equal to each other:
$10 + ($3 times x) = $15 + ($2 times x)
Solving the equation for x, we subtract $2x from both sides, which gives us: $10 + x = $15
Subtracting $10 from both sides gives us: x = $5
Therefore, after 5 rentals, the cost will be the same at both video clubs, and that cost will be: $10 + ($3 times 5) = $25

Answered by qwarrow | 2024-06-25

The costs at Video Club A and Video Club B will be the same after 5 movie rentals. At this amount of rentals, the total cost will be $25. The equation derived from setting the cost equations equal to each other was solved to find 'x' as 5.
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Answered by Anonymous | 2024-12-20