Suppose an investment of $1,800 doubles in value every 7 years. How much is the investment worth after 42 years?

x=2^n(1800) x=2^6(1800) x=$115,200

Answered by runescapememo8 | 2024-06-10

The investment in 42 years will become $115199.88 ;

Answered by SociometricStar | 2024-06-12

After 42 years, the investment of $1,800 that doubles every 7 years will be worth $115,200. This is calculated by determining the number of doubling periods in 42 years, which is 6, and applying the doubling formula. Therefore, the investment grows significantly due to the power of exponential growth.
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Answered by SociometricStar | 2024-12-23