Solve for x: [tex]\log_6(4x - 8) = 3[/tex]

0\to4x > 8\to x > 2\to x\in(2;\ \infty)\\\\(*)\ 4x-8=6^3\\\\4x=216+8\\\\4x=224\ \ \ \ /:4\\\\x=56\in D"> l o g 6 ​ ( 4 x − 8 ) = 3 ( ∗ ) D : 4 x − 8 > 0 → 4 x > 8 → x > 2 → x ∈ ( 2 ; ∞ ) ( ∗ ) 4 x − 8 = 6 3 4 x = 216 + 8 4 x = 224 / : 4 x = 56 ∈ D

Answered by Anonymous | 2024-06-10

4x-8=6^3 4x-8=216 4x=224 x=56

Answered by usagirlbibi | 2024-06-10

To solve lo g 6 ​ ( 4 x − 8 ) = 3 , we rewrite it in exponential form to find 4 x − 8 = 216 . This leads to the solution x = 56 , which is valid within the domain of the original equation.
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Answered by Anonymous | 2024-10-15