Solve the following system of linear equations by substitution:

1. \(8x - y = -13\)
2. \(6x - 3y = 15\)

{ 8 x − y = − 13 6 x − 3 y = 15 ​ { − y = − 8 x − 13 ∗ ( − 1 ) 6 x − 3 y = 15 ​ { y = 8 x + 13 6 x − 3 ( 8 x + 13 ) = 15 ​ { y = 8 x + 13 6 x − 24 x − 39 = 15 ​
{ y = 8 x + 13 6 x − 24 x = 15 + 39 ​ { y = 8 x + 13 − 18 x = 54 / : ( − 18 ) ​ { y = 8 ∗ ( − 3 ) + 13 x = − 3 ​ { y = − 24 + 13 x = − 3 ​ { y = − 11 x = − 3 ​

Answered by Lilith | 2024-06-10

Rearrange 8x-y=-13 to y=8x+13 Substitute this in so: 6x-3(8x+13)=15 6x-24x-39=15 -18x-39=15 -18x=54 x=-3
Substitute x into 1st equation: Y=(8*-3)+13 Y=-24+13 Y=-11

Answered by scazarockin | 2024-06-10

To solve the system of equations, we first express y in terms of x using the first equation. Then, we substitute this expression into the second equation, simplify, and solve for x. Finally, we substitute back the value of x to find y, leading us to the solution (x, y) = (-3, -11).
;

Answered by Lilith | 2024-10-13