Well the L and the W could be 75 and 95 Because 75 + 75 + 95 + 95= 340 And 75 x 95= 7125 Same Perimeter, different Area Glad to Help!
First, let's get the perimeter of the rectangle: P = 2 W + 2 L P = 130 m + 210 m P = 340 m Then, let's get the area of the bigger one: A = W L A = 65 m ∗ 105 m A = 6825 m 2
Then let's try using a rectangle with a smaller ratio: P = 100 m + 240 m P = 340 m Then: A = 50 m ∗ 120 m A = 6000 m 2
If you used a square: P = 170 + 170 P = 340 A = W L A = 8 5 2 A = 7225
There you have it. A rectangle with a smaller area with the same perimeter. What does it show? The smaller the difference you get from width and length, the larger the area is.
To find a rectangular field with the same perimeter (340 meters) and a smaller area than the original (6825 m²), you can set dimensions such as (90 meters width, 80 meters length) giving an area of 7200 m², or (110 meters width, 60 meters length) giving an area of 6600 m². Both options satisfy the conditions required.
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