Solve the following system of equations:

1. [tex]3x + y = 5[/tex]
2. [tex]2x - 2y = -2[/tex]

3 x + y = 5 / ∗ 2 2 x − 2 y = − 2 6 x + 2 y = 10 2 x − 2 y = − 2 + − − − − − 8 x = 8 / : 8 x = 1 3 ∗ 1 + y = 5 y = 5 − 3 y = 2 A n s w er : x = 1 y = 2

Answered by Lilith | 2024-06-10

3x+y=5 2x-2y=-2 x+3y=7 x+3y-3y=7-3y x=7-3y 3(7-3y)+y=5 21-9y+y=5 21-8y=5 21-21-8y=5-21 8y=-16 8y/8=-16/8 y=-2 x=7/3

Answered by runescapememo8 | 2024-06-10

The solution to the system of equations 3 x + y = 5 and 2 x − 2 y = − 2 is x = 1 and y = 2 . We can verify this by substituting these values back into the original equations. The ordered pair satisfying both equations is ( 1 , 2 ) .
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Answered by Lilith | 2024-10-30