33-6= 27 27 divide by 2 will be 13.5. so the answer is 13.5
**Answer:Use A for third graders, B for fourth graders, and C for fifth graders. **
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**33 = A + B + C **
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**Since there are three variables, you need to come up with two other equations to substitute in. **
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**C = 6 + A Since there are six more fifth graders than third graders. **
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**A = B Since there is an equal amount of third and fourth graders. **
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**Since A is in both equations, lets put each variable in terms of A. **
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**B = A **
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**C = 6 + A **
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**So: A+A+A+6=33 **
**A+A+A=27 Since you subtract six from both sides. **
**3A=27 Since you combine all three A's. **
**A=9 Since you divide both sides by three. **
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**Therefore, since A is the number of third graders, there are 9 third graders. ** ;
There are 9 3rd grade students in the band. This was found by setting up equations based on the relationships between the grades and the total number of students. The verification shows that the total adds up correctly to 33 students.
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