se c 2 θ 1 = co s 2 θ L = ( cos θ 1 ) 2 1 = co s 2 θ 1 1 = 1 : co s 2 θ 1 = 1 ⋅ 1 co s 2 θ = co s 2 θ = R
Yes, s e c 2 ( θ ) 1 is the same as cos 2 ( θ ) . This is derived from the definition of secant as the reciprocal of cosine. Thus, both expressions are equivalent.
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