Find the equation of the line through the point (2, 5) that cuts off the least area from the first quadrant. Give your answer using the form below:
[tex]y-A = B(x-C)[/tex]
Answer (2)
The answer is....... No problem. 5-a=b (2-5c)
The equation of the line through the point (2, 5) that minimizes the area cut off from the first quadrant is given by y − 5 = − 1 ( x − 2 ) . This line has a slope of -1 and passes through the specified point. It can represent the minimum area triangle formed in the first quadrant.
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