15 x 2 − 10 x − 5 = 0 a = 15 , b = − 10 c = − 5 Δ = b 2 − 4 a c = ( − 10 ) 2 − 4 ∗ 15 ∗ ( − 5 ) = 100 + 300 = 400 x 1 = 2 a − b − Δ = 2 ∗ 15 10 − 400 = 30 10 − 20 = 30 − 10 = − 3 1 x 2 = 2 a − b + Δ = 2 ∗ 15 10 + 400 = 30 10 + 20 = 30 30 = 1 15 x 2 − 10 x − 5 = 15 ( x + 3 1 ) ( x − 1 ) = ( 15 x + 3 1 ∗ 15 ) ( x − 1 ) = ( 15 x + 5 ) ( x − 1 ) A n s w er : 15 x 2 − 10 x − 5 = ( 15 x + 5 ) ( x − 1 )
15x^2 - 10x - 5 (3x + 1) (5x - 5)
If it tells you to solve it, set each part in parentheses and solve. What you end up will be your 2 final answers.
The expression 15 x 2 − 10 x − 5 can be factored as 5 ( 3 x + 1 ) ( x − 1 ) . First, we factor out the greatest common factor and then factor the quadratic expression. The final factored form involves recognizing numbers that fit the multiplication and addition conditions to split the middle term.
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