How do you solve for \( y \) in the equation \(\frac{y-1}{x+3} = -\frac{3}{4}\)?

x + 3 y − 1 ​ = − 4 3 ​ x + 3  = 0 x  = − 3 D = R ∖ { − 3 }
4 ( y − 1 ) = 3 ( x + 3 ) 4 y − 4 = 3 x + 9 4 y = 3 x + 9 + 4 4 y = 3 x + 13 \/ : 4 y = 4 3 ​ x + 4 13 ​

Answered by Lilith | 2024-06-10

To solve x + 3 y − 1 ​ = − 4 3 ​ , we first cross-multiply, then distribute, and finally isolate y to obtain y = − 4 3 ​ x − 4 5 ​ .
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Answered by Lilith | 2024-12-24