If \( x \) is a real number such that \( x^3 = 64 \), then \( x^2 + \sqrt{x} = \)?

If x³=64 ,x=∛64=4 x²=16 √x=4 x²+√x=16+2 ⇒18

Answered by Sitara | 2024-06-10

x 3 = 64 x = 3 64 ​ x = 4 x 2 + x ​ = 4 2 + 4 ​ = 16 + 2 = 18

Answered by Lilith | 2024-06-10

The value of x is determined from the equation x 3 = 64 to be 4. Substituting this value into the expression x 2 + x ​ yields a final result of 18. Therefore, x 2 + x ​ = 18 .
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Answered by Anonymous | 2024-09-05