f ( x ) = 7 x + 3 f ( 5 ) s u b s t i t u t e 5 → x f ( 5 ) = 7 ⋅ 5 + 3 = 35 + 3 = 38 f ( x + 8 ) s u b s t i t u t e x + 8 → x f ( x + 8 ) = 7 ( x + 8 ) + 3 = 7 x + 56 + 3 = 7 x + 59 f ( − x ) s u b s t i t u t e − x → x f ( − x ) = 7 ⋅ ( − x ) + 3 = − 7 x + 3
To evaluate the function f(x) = 7x + 3 for f(5), f(x+8), and f(-x), we substitute the given values into the function, which results in f(5) = 38, f(x+8) = 7x + 59, and f(-x) = -7x + 3.
To evaluate the function f(x) = 7x + 3 at different values, we substitute the values into the function and simplify.
f(5): Substitute x with 5. f(5) = 7(5) + 3 = 35 + 3 = 38.
f(x+8): Substitute x with x+8. f(x+8) = 7(x + 8) + 3 = 7x + 56 + 3 = 7x + 59.
f(-x): Substitute x with -x. f(-x) = 7(-x) + 3 = -7x + 3.
By substituting the given values, we have found the simplified expressions for f(5) , f(x+8) , and f(-x) .
We evaluated the function f ( x ) = 7 x + 3 at x = 5 , yielding f ( 5 ) = 38 . For f ( x + 8 ) , we found f ( x + 8 ) = 7 x + 59 . Finally, for f ( − x ) , the result is f ( − x ) = − 7 x + 3 .
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