{ 0.4 x + 0.5 y = 2.5 / ∗ 7 1.2 x − 3.5 y = 2.5 { 2.8 x + 3.5 y = 17.5 1.2 x − 3.5 y = 2.5 + − − − − − − − − 4 x = 20 / : 4 x = 5
0.4 x + 0.5 y = 2.5 0.4 ∗ 5 + 0.5 y = 2.5 2 + 0.5 y = 2.5 ∣ − 2 0.5 y = 2.5 − 2 0.5 y = 0.5 : / 0.5 y = 1 { \x = 5 y = 1
The solutions to the system of equations are x = 5 and y = 1, found by using the elimination method. We multiplied the first equation to eliminate x and found y first, then substituted back to find x. This process resulted in the values of both variables in the system.
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