The length of a rectangle is 50 feet less than its width. If the perimeter of the field is 840 feet, find the length of the field.
Answer (2)
l oo k a t t h e p i c t u re 2 a + 2 ( a − 50 ) = 840 2 a + 2 a − 100 = 840 4 a − 100 = 840 / + 100 4 a = 940 / : 4 a = 235 ( f t ) a − 50 = 235 − 50 = 185 ( f t ) A n s w er : l e n g h t = 185 f t ; w i d t h = 235 f t .
The length of the rectangle is 185 feet, while the width is 235 feet. This is determined through substituting variables into the perimeter equation. A step-by-step algebraic approach led to these dimensions.
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