Solve the quadratic equation:

\[ x^2 + 5x - 104 = 0 \]

0\ then\ x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=5^2-4\cdot1\cdot(-104)=25+416=441;\ \sqrt\Delta=\sqrt{441}=21\\\\x_1=\frac{-5-21}{2\cdot1}=\frac{-26}{2}=-13;\ x_2=\frac{-5+21}{2\cdot1}=\frac{16}{2}=8\\\\Answer:x=-13\ or\ x=8."> x 2 + 5 x − 104 = 0 a = 1 ; b = 5 ; c = − 104 Δ = b 2 − 4 a c ; i f Δ > 0 t h e n x 1 ​ = 2 a − b − Δ ​ ​ ; x 2 ​ = 2 a − b + Δ ​ ​ Δ = 5 2 − 4 ⋅ 1 ⋅ ( − 104 ) = 25 + 416 = 441 ; Δ ​ = 441 ​ = 21 x 1 ​ = 2 ⋅ 1 − 5 − 21 ​ = 2 − 26 ​ = − 13 ; x 2 ​ = 2 ⋅ 1 − 5 + 21 ​ = 2 16 ​ = 8 A n s w er : x = − 13 or x = 8.

Answered by Anonymous | 2024-06-10

You first have to factor and get (x-8)(x+13)=o and set them equal to zero x-8=0 x=8 x+13=0 x=-13

Answered by LauraPerezGonzales | 2024-06-10

The solutions to the quadratic equation x 2 + 5 x − 104 = 0 are x = − 13 and x = 8 . This is found using the quadratic formula after computing the discriminant. Both values satisfy the equation.
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Answered by Anonymous | 2025-02-19