Find the 8th term of the geometric sequence \([a_{n}, n = 1, 2, 3, \ldots]\) with a common ratio \(r = 0.5\) and first term \(a_{1} = 2\).
Answer (2)
a n = a 1 ⋅ q n − ‘1 a 1 = 2 ; q = 0.5 = 2 1 a 8 = a 1 ⋅ q 8 − 1 = a 1 ⋅ q 7 a 8 = 2 ⋅ ( 2 1 ) 7 = 2 ⋅ 2 7 1 = 2 ⋅ 128 1 = 64 1 A n s w er : a 8 = 64 1
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