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In Mathematics / High School | 2014-04-17

Which of the ordered pairs is not a function?

1. (0, 9), (9, 0), (1, 2), (3, 4)
2. (0, 1), (-1, 0), (1, 2), (3, 2)
3. (2, 3), (3, 4), (4, 5), (5, 6)
4. (2, 3), (2, 4), (4, 5), (4, 6)

Asked by Sarah7143

Answer (2)

A n s w er : 4 ) b ec a u se ( 2 ; 3 ) → x = 2 an d y = 3 ( 2 ; 4 ) → x = 2 an d y = 4 f or t hi s s am e " x " y = 3 an d y = 4 an d ( 4 ; 5 ) → x = 4 an d y = 5 ( 4 ; 6 ) → x = 4 an d y = 6 f or t hi s s am e " x " y = 5 an d y = 6

Answered by Anonymous | 2024-06-24

Option 4 is not a function because it has the x-value 2 associated with two different y-values, 3 and 4. Therefore, it violates the definition of a function. The other options consist of unique x-values, making them functions.
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Answered by Anonymous | 2024-10-10

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