(105+105+105+x)/4=110 multiply both sides by 4 105+105+105+x=440 315+x=440 x=125
The IQ of the fourth person is 125, calculated by subtracting the combined IQ of the first three individuals (315) from the total IQ (440) for all four individuals with an average of 110. This results in a final IQ of 125 for the fourth person. Thus, if each of the first three has an IQ of 105, the fourth must have an IQ of 125 to maintain the stated average.
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