How do you factor [tex]16x^2 - 72xy + 81y^2[/tex]?

16 x 2 − 72 x y + 81 y 2 = ( 4 x ) 2 − 2 ⋅ 4 x ⋅ 9 y + ( 9 y ) 2 = ( 4 x − 9 y ) 2 = ( 4 x − 9 y ) ( 4 x − 9 y ) ( a − b ) 2 = a 2 − 2 ab + b 2

Answered by Anonymous | 2024-06-10

use the perfect square trinomial method. since 16x² is a perfect square and so is 81y² your answer would be (4x-9y)² when u multiply that out it will give u 16x²-72xy+81y²

Answered by gom3z18 | 2024-06-10

The expression 16 x 2 − 72 x y + 81 y 2 factors as ( 4 x − 9 y ) 2 . This is because it fits the format of a perfect square trinomial. Therefore, it results in the factorization ( 4 x − 9 y ) ( 4 x − 9 y ) .
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Answered by Anonymous | 2024-09-30