In humans, having freckles is the result of a dominant gene, and not having freckles is a recessive trait. If a freckled man who is homozygous for this trait has a child with a woman who does not have freckles, which of the following best describes how their child would most likely appear?
A. Their child would not have freckles if the father passes on the recessive allele.
B. Their child would have freckles.
C. Their child would not have freckles.
D. Their child would have freckles since the mother is a carrier for freckles.
Answer (3)
Its b because if you cross FF(freckles) and ff (no freckles) using punnet square or any method you will get 100% Ff . Since its recesive Ff means having freckles so the answer is b their child would have freckles
The answer is C. Draw a Punnett square.
The child of a freckled father (homozygous FF) and a mother without freckles (homozygous ff) will have freckles due to receiving the dominant allele F from the father. Thus, the child will have the genotype Ff, which expresses the freckled trait. The correct answer is B: Their child would have freckles.
;
