6 x 2 − 7 x + 2 = 0 a = 6 , b = − 7 , c = 2 Δ = b 2 − 4 a c = ( − 7 ) 2 − 4 ∗ 6 ∗ 2 = 49 − 48 = 1 x 1 = 2 a − b − Δ = 2 ∗ 6 7 − 1 = 12 7 − 1 = 12 6 = 2 1 x 2 = 2 a − b + Δ = 2 ∗ 6 7 + 1 = 12 7 + 1 = 12 8 = 3 2
To solve 6 x 2 − 7 x + 2 = 0 by completing the square, first convert it to a simpler form by isolating the variable. Then, complete the square and solve for x . The final solutions are x = 3 2 and x = 2 1 .
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